PCl5 has a shape of trigonal bipyramid whereas IF5 has the shape of a square pyramid' It is due to

In PCl5 molecule, the central P atom has 5 bond pairs of electrons and 0 lone pairs of electrons. It undergoes sp3d hybridization which results in trigonal bipyramidal geometry. In IF5 molecule, the central iodine atom has 5 bond pairs of electrons and 1 lone pair of electrons. It undergoes sp3d2 hybridization. The expected geometry is octahedral and the actual geometry is square pyramidal.

PCl5 has a shape of trigonal bipyramid whereas IF5 has the shape of a square pyramid' It is due to

In PCl5 molecule, the central P atom has 5 bond pairs of electrons and 0 lone pairs of electrons. It undergoes sp3d hybridization which results in trigonal bipyramidal geometry. In IF5 molecule, the central iodine atom has 5 bond pairs of electrons and 1 lone pair of electrons. It undergoes sp3d2 hybridization. The expected geometry is octahedral and the actual geometry is square pyramidal.

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PCl₅ has a shape of trigonal bipyramid whereas IF₅ has the shape of a square pyramid' It is due to

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presence of lone pair on I which is oriented so as to minimise repulsion, while P in PCI₅ has no unshared Pair

octet of P is complete while that of I is incomplete

P and I are non-metals

F and Cl have different extent of repulsion

answer is A.

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Detailed Solution

In PCl₅ molecule, the central P atom has 5 bond pairs of electrons and 0 lone pairs of electrons. It undergoes sp³d hybridization which results in trigonal bipyramidal geometry.

In IF₅ molecule, the central iodine atom has 5 bond pairs of electrons and 1 lone pair of electrons. It undergoes sp³d² hybridization. The expected geometry is octahedral and the actual geometry is square pyramidal.

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