Q.

 PCl5PCl3+Cl2
If the equilibrium constant (Kc)  for the above reaction at 500 K is 1.79 and the equilibrium concentration of  PCl5 and  PCl3  are 1.41M  and 1.59M  respectively. Then the concentration of  Cl2  is approximately

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a

0.59 M 

b

1.26 M  

c

1.59 M

d

3.59 M 

answer is A.

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Detailed Solution

KC=[PCl3][Cl2][PCl5] [Cl2]=1.79×1.411.59=1.5871.59M

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