Q.

PCl5(g) decomposes according to following reaction,

PCl5(g)PCl3(g)+Cl2(g)

Calculate density (in g/L) of mixture at 24atm and 300K, when PCl5(g) undergo 50% decomposition. 

R=0.08atmLmol1K1

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answer is 139.

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Detailed Solution

In the given reaction we have;

PCl5(g)PCl3(g)+Cl2(g)PM=dRTd=24×208.51.5×10.08×1300

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PCl5(g) decomposes according to following reaction,PCl5(g)→PCl3(g)+Cl2(g)Calculate density (in g/L) of mixture at 24atm and 300K, when PCl5(g) undergo 50% decomposition. R=0.08atmLmol−1K−1