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Q.

PCl5(s) reacts with H2O(l) according to the equation:

PCl5(s)+4H2O(l)H3PO4(aq)+5HCl(aq) What is ΔH for this reaction in kJ/mol1?

SubstanceΔHf,kJ/mol
PCl5(s)-443.5
H2O(l)-285.8
H3PO4(aq)-1284.4
HCM(aq)-167.1

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a

-722.2

b

-533.2

c

533.2

d

722.2

answer is B.

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Detailed Solution

For the given values, change in enthalpy,

ΔH=167.1×51284.4+285.8×4+443.5=533.2

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