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Per two gram of charcoal a gas is adsorbed by 0.1 g and 0.2 g at 10 torr and 80 torr pressure respectively. The value of “n” in Freundlich adsorption isotherm is?

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Detailed Solution

$\begin{array}{l} \frac{x}{m} = {kP}^{1 / n} \\ \frac{0.1}{2} = k {(10)}^{1 / n} . . . (1) \\ \frac{0.2}{2} = k {(80)}^{1 / n} . . . (1) \end{array}$

$\frac{0.1}{0.2} = {(\frac{10}{80})}^{1 / n} {(\frac{1}{2})}^{1} = {(\frac{1}{2})}^{1 / 3} n = 3$

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