p^H of 0.01 M Weak monoprotic acid is (K_a of acid is 4 x 10^-4 )

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2.699

3.301

4.602

3.3979

answer is C.

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Detailed Solution

$\begin{array}{l} [H^{+}] = \sqrt{{CK}_{a}} \\ [H^{+}] = \sqrt{0 .01 \times 4 \times 10^{- 4}} \\ [H^{+}] = 2 \times 10^{- 3} \\ p^{H} = 3 - \log 2 \\ p^{H} = 2 .699 \end{array}$

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