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pH of 0.1 M monobasic acid is found to be 2. Hence its osmotic pressure at a given temp. T K is :

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0.11 RT

0.1 RT

1.1 RT

0.01 RT

answer is B.

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Detailed Solution

$[H^{+}] = c α; 10^{- 2} = 0.4 \times α Here, \Rightarrow α = 0.1 i = 1 + α = 1.1 Thus, π = 0.1 \times 1.1 \times R \times T$

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