Q.

pH of saturated aqueous solution of Ba(OH)2  is 12. Identify the correct statement.

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a

The solubility product of Ba(OH)2  is   5×107M3

b

The solubility of Ba(OH)2 in a buffer solution of  pH=1 is 5×105moles/L

c

The solubility of Ba(OH)2  in a buffer solution of  pH=13 is 5×105moles/L

d

The solubility of Ba(OH)2 decreases in presence of  NH4Cl

answer is A, D.

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Detailed Solution

Since  pH=12
    pOH=1412=2  [OH]=102M
 We know  Ba(OH)2 Ba+++2OH
      [Ba++]=1022M     KSP=[Ba++][OH]2=(1022)×(102)2=5×107M3

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