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Q.

pH of $0.1 M {Na}_{2} {HPO}_{4}$ and $0.2 M {NaH}_{2} {PO}_{4}$ are respectively: $({pK}_{a}$ for $H_{3} {PO}_{4}$ are 2.2, 7.2 and 12.0)

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a

9.6, 4.7

b

4.7, 5.6

c

5.6, 4.7

d

4.7, 9.6

answer is B.

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Detailed Solution

pH of $0.1 M {Na}_{2} {HPO}_{4}$

$\underset{({NaH}_{2} {PO}_{4})}{{pH}_{2}} = \frac{2.2 + 7.2}{2} = 4.7$

pH of $0.2 M {NaH}_{2} {PO}_{4}$

$\underset{({NaH}_{2} {PO}_{4})}{{pH}_{2}} = \frac{2.2 + 7.2}{2} = 9.6$

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