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pH of $0.1 M NaA$ solution is: Given: ${(K_{b})}_{A^{-}}$ $= 10^{- 9}$

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Detailed Solution

$\begin{array}{l} \begin{array}{c} \underset{0.1 - x}{A^{-}} + H_{2} O ⇌ \underset{x}{HA} + {\underset{x}{OH}}^{-} \end{array} \\ \frac{x^{2}}{0.1} = 10^{- 9} \\ \Rightarrow 1 x = 10^{- 5} or pOH = 5 \end{array}$

Thus, pH of $0.1 M NaA$ solution is 9.

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