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Phenol is heated with CCl₄ and alc. KOH to give salicylic acid, this reaction is known as :

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Reimer-Tiemann reaction

Clemmensen reduction

Friedel-Crafts reaction

Rosenmund reaction

answer is B.

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Detailed Solution

When phenol is heated with carbon tetrachloride (CCl₄) in the presence of alcoholic KOH, it gives salicylic acid.

This reaction is known as the Reimer–Tiemann reaction.

Reaction:

C_6H_5OH + CCl_4 + 3KOH \;\;\xrightarrow{\Delta}\;\; o-HO–C_6H_4–COOH \; (Salicylic\; acid)

$C$ $6$ $$ $H$ $5$ $$ $OH$ $+$ $CCl$ $4$ $$ $+$ $3$ $KOH$ $Δ$ $$ $o$ $-$ $HO$ $-$ $C$ $6$ $$ $H$ $4$ $$ $-$ $COOH$ $($ $Salicylicacid$ $)$

In this reaction, the –CHO or –COOH group is introduced at the ortho position of phenol due to the activating effect of the –OH group.

Final Answer: The reaction is called the Reimer–Tiemann reaction.

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