${PhNH}_{2}$ and $PhNHMe$ can be differentiated by :

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${CHCl}_{3}, KOH$

${NaNO}_{2}, HCl$

both (a) and (b)

none of these

answer is C.

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Detailed Solution

$1^{o}$ and $2^{o}$ Both the isocyanide test and diazotization can be used to identify amines. ${PhNH}_{2}$ is $1^{o}$ An offensive odour is produced by the amine and positive isocyanide test while $PhNHMe$ never does.

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