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$p^{H}$ of 0.01M $NaOH$ solution is ‘X’ & 0.05M $H_{2} {SO}_{4}$ is ‘Y’. Value of (X–Y) is equal to

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10.7

0.7

answer is B.

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Detailed Solution

$[{OH}^{-}] = (0 .01 M) 1$
$p^{OH} = 2$
$p^{H} = 12$
$[H^{+}] = (0 .05 \times 2) M$
$p^{H} = 1; X - Y = 11$

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