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Q.

$p^{H}$ of 0.1 (M) BOH (weak base) is found to be 12. The solution at temperature T K will display an osmotic pressure equal to

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a

0.01 RT

b

0.01 ${(RT)}^{2}$

c

0.11 RT

d

1.1 RT

answer is C.

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Detailed Solution

$\begin{array}{l} pH = 12, \\ pOH = 14 - 12 = 2, \\ [{OH}^{-}] = 10^{- 2} \\ [{OH}^{-}] = Cα \\ [10^{- 2}] = 0 .1 α \\ α = 0 .1 \\ i = 1 + (n - 1) α \\ = 1 + (2 - 1) \times 0 .1 \\ = 1 .1 \\ π = iCRT = 1 .1 \times 0 .1 RT = 0 .11 RT . \end{array}$

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