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Q.

$P^{H}$ of $10^{-3} M$ aqueous solution of sodium acetate is [ $P^{ka}$ of $C H_{3} C O O H$ is 4.8]

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a

7.9

b

8.1

c

6.2

d

12

answer is A.

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Detailed Solution

$= \frac{1}{2} [P^{kw} + P^{ka} + logC]$

$= \frac{1}{2} [14 + 4.8 - 3] = 7.9$

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