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$p H$ of a lemon water bottle is $3$ , and that of orange juice is $4$ . Calculate the $p H$ of final solution obtained by mixing above solutions in volume ratio $1 : 2$ respectively. (Assuming there is no chemical reaction.) (Given $\log 2 = 0.30$ )

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$0.4$

$3.4$

$1.4$

$2.4$

answer is A.

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Detailed Solution

$1 x 10^{- 3} + 2 x 10^{- 4} = 3 x [H^{+}] 10^{- 3} + 0.2 x 10^{- 3} = 3 x [H^{+}] [H^{+}] = \frac{1.2 x 10^{- 3}}{3} = 0.4 x 10^{- 3} = 4 x 10^{- 4} p H = - \log [H^{+}] = 4 - \log 4 = 4 - 0.6 = 3.4$

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