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Phosgene gas ( $C O C l_{2}$ ) dissociates to carbon monoxide gas and chlorine gas with a change of pressure from 450 mm Hg to 600 mm Hg. If volume and temperature remain constant throughout the experiment, the value of $K_{p}$ is ______.

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answer is 75.

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Detailed Solution

It is given to calculate the value of $K_{p}$ .

$C O C l_{2 (g)} ⇌ C O_{(g)} + C l_{2 (g)}$

$K_{(} p) = \frac{[C O] [C l_{2}]}{C O C l_{2}}$

Initial:	450	-	-
Change:	-x	+x	+x
At equilibrium	450-x	+x	+x

450 – x + x + x = 600

Therefore x = 150

$K_{(} p) = \frac{[C O] [C l_{2}]}{C O C l_{2}}$

= $\frac{[150] [150]}{450 - 150}$

= $\frac{22500}{300}$ = 75.

Hence, the answer is 75.

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