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Q.

Phosphorus pentachloride dissociated as follows in a closed vessel, PCl5(g)PCl3(g)+Cl2(g) If total pressure at equilibrium of the reaction. Mixture is P and degree of dissociation of PCl5 is x, the partial pressure of PCl3 will be

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a

2x1xP

b

xx-1P

c

x1xP

d

x1+xP

answer is D.

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Detailed Solution

PCl51x PCl3x+Cl2x
At equilibrium
Total moles = 1 – x + x + x = 1 + x
Partial pressure of  PCl3=x1+xP
Partial pressure = Total pressure x mole fraction of PCl3

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