Photochemical fluorination is explosive, while iodination is too slow to occur. The
number of following statements explain the correct reason is/ are
(1) Bond dissociation energy of $I_2$ is minimum
(2) Formation of ${\mathrm{CH}}_3-\mathrm{F}$ is most exothermic
(3) Formation H - F is most exothermic, while formation of HI is endothermic
(4) The bond dissociation energies order are ${\mathrm{F}}_2<{\mathrm{Cl}}_2<{\mathrm{Br}}_2<{\mathrm{I}}_2$