Photochemical fluorination is explosive, while iodination is too slow to occur. The reason for this
is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Bond dissociation energy of $I_{2}$ is minimum

Formation of ${CH}_{3} - F$ is most exothermic

Formation of HF is exothermic and that of HI is endothermic.

$F_{2}$ has lower bond dissociation energy than $I_{2}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Due to the low bond dissociation energy of F₂, the fluorination of hydrocarbons with pure fluorine gas occurs explosive and releases a large amount of heat.

Whereas, high bond dissociation energy of I₂, the iodination of hydrocarbons requires a large amount of heat.

Therefore, formation of ${CH}_{3} - F$ and HF is exothermic whereas that of HI is endothermic.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!