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Photochemical fluorination is explosive, while iodination is too slow to occur. The reason for this
is

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Bond dissociation energy of $I_{2}$ is minimum

Formation of ${CH}_{3} - F$ is most exothermic

Formation of HF is exothermic and that of HI is endothermic.

$F_{2}$ has lower bond dissociation energy than $I_{2}$

answer is B.

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Detailed Solution

Due to the low bond dissociation energy of F₂, the fluorination of hydrocarbons with pure fluorine gas occurs explosive and releases a large amount of heat.

Whereas, high bond dissociation energy of I₂, the iodination of hydrocarbons requires a large amount of heat.

Therefore, formation of ${CH}_{3} - F$ and HF is exothermic whereas that of HI is endothermic.

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