Photoelectric emission is observed from a metallic surface for frequencies $ν_{1}$ and $ν_{2}$ of the incident light $(ν_{1} > ν_{2})$ . If the maximum values of kinetic energy of the photo electrons emitted in the two cases are in the ratio 1 : n, then the threshold frequency of the metallic surface is:

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$\frac{v_{1} - v_{2}}{n - 1}$

$\frac{n v_{1} - v_{2}}{n - 1}$

$\frac{n v_{2} - v_{1}}{n - 1}$

$\frac{v_{1} - v_{2}}{n}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$E_{1} = h (v_{1} - v_{0}) and E_{2} = h (v_{2} - v_{0})$

Dividing them, we get

$\frac{E_{2}}{E_{1}} = \frac{v_{2} - v_{0}}{v_{1} - v_{0}} = \frac{n}{1}$

Hence, we have:

$n = \frac{v_{2} - v_{0}}{v_{1} - v_{0}}$

which gives $v_{0} = \frac{n v_{1} - v_{2}}{(n - 1)}$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test