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Q.

Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.

(a) 5m=60(10, 5, 12, 15)
(b) n+12=20(12, 8, 20, 0)
(c) p-5=5(0, 10, 5, -5)
(d) q2=7(7, 2, 10, 14)
(e) r-4=0(4, -4, 8, 0)
(f) x+4=2(-2, 0, 2, 4)

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Detailed Solution

(a) 5m=60

For m = 10, LHS = 5 x 10 = 50, RHS = 60
Thus, LHS ≠ RHS
So, m = 10 is not the solution to the equation
For m = 5, LHS = 5×5 = 25, RHS = 60
Thus, LHS ≠ RHS
So, m = 5 is not the solution to the equation
For m = 12, LHS = 5 x 12 = 60, RHS = 60
Thus, LHS = RHS
So, m = 12 is the solution to the equation
For m = 15 LHS = 5 x 15 = 75, RHS = 60
Thus, LHS ≠ RHS
So, m = 15 is not the solution to the equation

(b) n+12=20
For n = 12, LHS = 12 + 12 = 24, RHS = 20
Thus, LHS ≠ RHS
So, n = 12 is not the solution to the equation
For n = 8, LHS = 8 + 12 = 20, RHS = 20
Thus, LHS = RHS
So, n = 8 is the solution to the equation
For n = 20, LHS = 20 + 12 = 32, RHS = 20
Thus, LHS ≠ RHS
So, n = 20 is not the solution to the equation
For n = 0, LHS = 0 + 12 = 12, RHS = 20
Thus, LHS ≠ RHS
So, n= 0 is not the solution to the equation

(c) p-5=5
For p = 0, LHS = 0 – 5 = -5, RHS = 5
Thus, LHS ≠ RHS
So, p = 0 is not the solution to the equation
For p = 10, LHS = 10 – 5 = 5, RHS = 5
Thus, LHS = RHS
So, p = 10 is the solution to the equation
For p = 5, LHS = 5-5=0, RHS = 5
Thus, LHS ≠ RHS
So, p = 5 is not the solution to the equation
For p = -5, LHS = -5 – 5 = - 10, RHS = 5
Thus, LHS ≠ RHS
So, p = -5 is not the solution to the equation

(d) q2=7
For q = 7, LHS = 7/2 , RHS = 7
Thus, LHS ≠ RHS
So, q = 7 is not the solution to the equation
For q = 2, LHS = 2/2 = 1, RHS = 7
Thus, LHS ≠ RHS
So, q = 2 is not the solution to the equation
For q = 10, LHS = 10/2 = 5, RHS = 7
Thus, LHS ≠ RHS
So, q = 2 is not the solution to the equation

For q = 14, LHS = 14/2 = 7, RHS = 7
Thus, LHS ≠ RHS
So, q = 14 is the solution to the equation

(e) r-4=0 
For r = 4, LHS = 4 – 4 = 0, RHS = 0
Thus, LHS = RHS
So, r = 4 is the solution of the equation
For r = -4, LHS = -4 – 4 = -8, RHS = 0
Thus, LHS ≠ RHS
So, r = -4 is not the solution of the equation
For r = 8, LHS = 8 – 4 = 4, RHS = 0
Thus, LHS ≠ RHS
So, r = 8 is not the solution of the equation
For r = 0, LHS = 0 – 4 = – 4, RHS = 0
Thus, LHS ≠ RHS
So, r = 0 is not the solution of the equation

(f) x+4=2
For x = -2, LHS = -2 + 4 = 2, RHS = 2
Thus, LHS = RHS
So, x = -2 is the solution of the equation
For x = 0, LHS = 0 + 4 = 4, RHS = 2
Thus, LHS ≠ RHS
So, x = 0 is not the solution of the equation
For x = 2, LHS = 2 + 4 = 6, RHS = 2
Thus, LHS ≠ RHS
So, x = 2 is not the solution of the equation
For r = 4, LHS = 4 + 4 = 8, RHS = 2
Thus, LHS ≠ RHS
So, x = 4 is not the solution of the equation

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