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Q.

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in :

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a

$1 \frac{13}{17} hours$

b

$2 \frac{8}{11} hours$

c

$3 \frac{9}{17} hours$

d

$4 \frac{1}{2} hours$

answer is C.

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Detailed Solution

Net part filled in 1 hour

$= (\frac{1}{5} + \frac{1}{6} - \frac{1}{12}) = \frac{17}{60}$

$∴$ The tank will be full in $\frac{60}{17} hrs i.e., 3 \frac{9}{17} hrs.$

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