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$p^{k_{a}}$ of $C H_{3} C O O H$ Is 4.82. $p^{k_{b}}$ of $N H_{4} O H$ Is 4.78. pH of ammonium acetate solution at 298 K is

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6.92

6.96

7.02

answer is C.

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Detailed Solution

$p^{H} = 7 + \frac{1}{2} (4.82) - \frac{1}{2} (4.78)$

$p^{H} = 7.02$

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