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Q.

pKa of CH3COOH is 4.6990. Kb of its conjugate base at same temperature is 

(antilog 0.6990= 5)

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a

9.3010

b

5 x 10-9

c

5 x 10-10

answer is C.

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Detailed Solution

pKb = 14 - 4.6990 = 9.3010

Kb = -10 + 0.6990 = 5 x 10-10

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pKa of CH3COOH is 4.6990. Kb of its conjugate base at same temperature is (antilog 0.6990= 5)