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Q.

pKb of NH3 is 4.74 and, PKb of A- , B- and C- are 4, 5 and 6 respectively. Aqueous solution of 0.01 M has pH in the increasing order as

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a

NH4C<NH4A<NH4B=7

b

NH4C<NH4B<NH4A

c

AII have equal pH being salt of weak acid and weak base

d

NH4A<NH4B<NH4C

answer is B.

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Detailed Solution

Salts (NH4A, NH4B, NH4C) are of weak acid and weak base.

pH=7+pKa2pKb2 Thus, greater the value of pKa of HA, greater the pH. pKbA,B,C A<B<C5 pKa(HA,HB,HC)H8C<HB9<HA10  Thus, pHNH4C<NH4B<NH4A

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