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Platinum crystallizes in a face-centered cubic crystal with a unit cell length $α$ . The distance between nearest neighbours is

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$α$

$a \frac{\sqrt{2}}{2}$

$a \frac{\sqrt{3}}{2}$

$a \frac{\sqrt{2}}{4}$

answer is C.

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Detailed Solution

We are informed that the FCC lattice is how platinum crystallises. As a result, the radius formula in the FCC lattice is as follows:

$4 r = \sqrt{2 a}$

where r = radius and a = edge length

The formula: is used to determine the nearest neighbour atom in the FCC lattice.

$2 r = \sqrt{2 a} / 2$ .

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