Please help Sahu decode the jail lock. Chach Choudhary gave Sabu a formula :

${\mathrm{f}}_1=\left(\frac{\mathrm{x}}{\mathrm{z}}\times \mathrm{y}\right);{\mathrm{f}}_2=\left(\frac{\mathrm{t}}{\mathrm{v}}\times \mathrm{u}\right);{\mathrm{f}}_3=\left(\frac{\mathrm{r}}{\mathrm{s}}\times \mathrm{w}\right)$

Sahu can open the lock if he finds the value of $3f_1+f_2+f_3=$ key where :

Number of triangular faces in a truncated tetrahedron = x
Number of hexagonal faces in a truncated tetrahedron = y$3\times \frac{4}{3}+2+2=8$

Number of corners in a truncated tetrahedron = z
Number of square faces in a truncated octahedron = t
Number of hexagonal faces in a truncated octahedron = u

Number of corners in a truncated octahedron = v
Number of triangular faces in a truncated cube = w
Number of octagonal faces in a truncated cube = r
Number of corners in a truncated cube = s
What is the KEY?