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Plots for $2 s$ orbital are:
$X, Y & Z$ are respectively

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$R, R^{2} a n d 4 π r^{2} R^{2}$

$4 π r^{2} R^{2}, R^{2} a n d R$

$R^{2}, 4 π r^{2} R^{2} a n d R$

$R^{2}, R a n d 4 π r^{2} R^{2}$

answer is B.

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Detailed Solution

Y will be definitely ‘R’ because value of R cannot be negative, thus X will be $R^{2}$ and Z will be $4 π r^{2} R .$ Z represents radial probability function; Its value will be zero at origin.

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