$\mathrm{p}=\sum _{\mathrm{n}=0}^{\infty }\frac{{\mathrm{x}}^{3\mathrm{n}}}{\left(3\mathrm{n}\right)!}, \mathrm{q}=\sum _{\mathrm{n}=0}^{\infty }\frac{{\mathrm{x}}^{3\mathrm{n}-2}}{(3\mathrm{n}-2)!}, \mathrm{r}=\sum _{\mathrm{n}=0}^{\infty }\frac{{\mathrm{x}}^{3\mathrm{n}-1}}{(3\mathrm{n}-1)!}$ then $\mathrm{p} + \mathrm{q} + \mathrm{r} =$

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