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Q.

$p O H$ of $0.1$ molar aqueous $N a C N$ solution found to be 2, then calculate value of dissociation constant of $H C N$ in its aqueous solution.

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a

$10^{- 11}$

b

$1.11 \times 10^{- 3}$

c

$9 \times 10^{- 12}$

d

$10^{- 2}$

answer is D.

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Detailed Solution

${CN}^{-} + H_{2} O ⇌ HCN + {OH}^{-}$

$0.1 - x$ $x$ $x$

$\frac{10^{- 14}}{K_{a}} = \frac{x^{2}}{0.1 - x}$

$x = 10^{- 2}$

$K_{a} = 9 \times 10^{- 12}$

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