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Q.

Points (t−1,2t+2) and (2t+1,t+1) are images of each other with respect of line ‘L’. If ‘L’ passes through (−1,0) then value of ‘t’ is

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a

−12

b

12

c

−32

d

32

answer is D.

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Detailed Solution

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AP=PB

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⇒t2+(2t+2)2=(2t+2)2+(t+1)2⇒t=−12

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