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Q.

Points $(t - 1, 2 t + 2)$ and $(2 t + 1, t + 1)$ are images of each other with respect of line ‘L’. If ‘L’ passes through $(- 1, 0)$ then value of ‘t’ is

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a

$\frac{- 1}{2}$

b

$\frac{1}{2}$

c

$\frac{- 3}{2}$

d

$\frac{3}{2}$

answer is D.

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Detailed Solution

detailed_solution_thumbnail

$A P = P B$

Question Image

$\Rightarrow \sqrt{t^{2} + {(2 t + 2)}^{2}} = \sqrt{{(2 t + 2)}^{2} + {(t + 1)}^{2}} \Rightarrow t = \frac{- 1}{2}$

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