Position ‘x’ verses time ‘t’ graph of two particles A and B are as shown in figure. Velocity of A is

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20 ms^-1 in the same direction of velocity of B

10 ms^-1, in the same direction of velocity of A

10 ms^-1, opposite to velocity of B

20 ms^-1, opposite to velocity of B

answer is B.

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Detailed Solution

Slope of x-t graph = velocity
$\begin{array}{l} \Rightarrow V_{B} = \frac{- 40}{4} = - 10 m s^{- 1} \\ S_{v e l} = V_{v e l} t \\ \Rightarrow (40 - 10) = (V_{A} + 10) \times 1 \end{array}$
$\Rightarrow V_{A} = 20 m s^{- 1},$ opposite to velocity of B

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