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Position (x) versus time (t) graph of two persons A and B as shown. Their relative velocity is $5 m s^{- 1}$ and velocity of A is $15 m s^{- 1}$ . The displacement of B when they met is

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125 m

75 m

50 m

200 m

answer is C.

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Detailed Solution

$V_{A B} = V_{A} - V_{B} \Rightarrow V_{B} = 15 - 5 = 10 {ms}^{- 1}$

$S_{B} = V_{B} t = 50 m$

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