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Potassium dichromate convert ${Sn}^{2 +} and I^{-}$ in acidic medium to

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I₂

${Sn}^{4 +}$

Sn and IO^-₃

both 1 and 2

answer is C.

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Detailed Solution

${Cr}_{2} O_{7}^{- 2} + 3 {Sn}^{+ 2} + 14 H^{+} ⟶ 3 {Sn}^{4 +} + 2 {Cr}^{3 +} + 7 H_{2} O {Cr}_{2} O_{7}^{- 2} + 6 I^{-} + 14 H^{+} \to 2 {Cr}^{+ 3} + 3 I_{2} + 7 H_{2} O$

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