Potassium permanganate on heating at 513K gives a product which is

In the process of breaking down into potassium manganate, manganese dioxide, and oxygen gas, potassium permanganate:
$2{\mathrm{KMnO}}_4\frac{\mathrm{\Delta }}{200°\mathrm{C}}\underset{\text{ Green }}{{\mathrm{K}}_2{\mathrm{MnO}}_4}+\underset{\text{ Black }}{{\mathrm{MnO}}_2}+{\mathrm{O}}_2$

The manganese oxidation state in  ${\mathrm{K}}_2{\mathrm{MnO}}_4 \mathrm{is} +6$, so it has one unpaired electron and it is paramagnetic and green in color.

Hence, the correct option (C).