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Potassium permanganate oxidizes oxalic acid to ${CO}_{2}$ in acidic media. The number of mole of ${KMnO}_{4}$ required to oxidize 0.5 mole of oxalic acid

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0.6

0.8

0.2

answer is A.

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Detailed Solution

n-factor of oxalic acid is 2;

n-factor of KMnO₄/H⁺ is 5;

2 moles KMnO₄/H⁺ oxidizes 5 moles oxalic acid.

x ………………………………0.5…………….

x=0.2 ;

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