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Q.

Potential energy of a body of mass 1kg free to move along x-axis is given by U(x)=x22xJ. If total mechanical energy of body is 2J. Then the maximum speed of the body is (assume only conservative force act on body)  

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a

3.5m/s

b

5m/s

c

5m/s

d

8m/s

answer is A.

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Detailed Solution

E=U+K.E
for Umin=dU(x)dx=0
then x=1
then Umin=12
m=1kgKE=12mv2=V22E=Umim+KE2=12+V22
then V=5m/s
 

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