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Q.

Power of a man who can chew 0.3 kg ice in one minute

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a

2400 cal s−1

b

400 cal s−1

c

4 cal s−1

d

24 cal s−1

answer is A.

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Detailed Solution

m=0.3kg,t=1min=60s

Power =wt=Qt=mLt=0.3×80×10360

power=400cal/s

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