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Power applied to a particle varies with time as $P = (3 t^{2} - 2 t + 1)$ watt. The change in K.E between $t = 2 s e c$ and $t = 4 s e c$ is _____ J

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16J

answer is D.

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Detailed Solution

$ΔKE = W = \int_{t_{1}}^{t_{2}} Pdt = \int_{2}^{4} (3 t^{2} - 2 t + 1) dt$

${[t^{3} - t^{2} + t]}_{2}^{4} = 46 J$

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