Power supplied to a particle of mass 2 kg varies with time as P=3t22 W (where, t is in second). If particle is rest at t = 0, then velocity of particle at time t = 2s will be

Work done, W=∫Pdt or, 12mv2=∫Pdt=∫023t22dt=4⇒ v=82=2 ms-1

Power supplied to a particle of mass 2 kg varies with time as P=3t22 W (where, t is in second). If particle is rest at t = 0, then velocity of particle at time t = 2s will be

Work done, W=∫Pdt or, 12mv2=∫Pdt=∫023t22dt=4⇒ v=82=2 ms-1

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Power supplied to a particle of mass 2 kg varies with time as $P = \frac{3 t^{2}}{2} W$ (where, t is in second). If particle is rest at t = 0, then velocity of particle at time t = 2s will be

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1 $m s^{- 1}$

4 $m s^{- 1}$

2 $m s^{- 1}$

2 $\sqrt{2}$ $m s^{- 1}$

answer is C.

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Work done, $W = \int P d t or, \frac{1}{2} m v^{2} = \int P d t = \int_{0}^{2} (\frac{3 t^{2}}{2}) d t = 4$

$\Rightarrow v = \sqrt{\frac{8}{2}} = 2 {ms}^{- 1}$

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Power supplied to a particle of mass 2 kg varies with time as P=3t22 W (where, t is in second). If particle is rest at t = 0, then velocity of particle at time t = 2s will be

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Power supplied to a particle of mass 2 kg varies with time as $P = \frac{3 t^{2}}{2} W$ (where, t is in second). If particle is rest at t = 0, then velocity of particle at time t = 2s will be