Power supplied to a particle of mass 2 kg varies with time as P=3t22 watt. Here t is in second. If velocity of particle at t =0 is v=0.The velocity of particle at time t = 2 s will be

From work energy thermo ΔKE = Wnetor K1−K1=∫Pdtor 12mv2= ∫0232t2dtor v2= t3220 or v= 2m/s

Power supplied to a particle of mass 2 kg varies with time as P=3t22 watt. Here t is in second. If velocity of particle at t =0 is v=0.The velocity of particle at time t = 2 s will be

From work energy thermo ΔKE = Wnetor K1−K1=∫Pdtor 12mv2= ∫0232t2dtor v2= t3220 or v= 2m/s

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Power supplied to a particle of mass 2 kg varies with time as $P = (\frac{3 t^{2}}{2})$ watt. Here t is in second. If velocity of particle at t =0 is $v = 0$ .The velocity of particle at time t = 2 s will be

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$2 \sqrt{2} m s^{- 1}$

1m/s

4m/s

2m/s

answer is C.

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From work energy thermo

$\begin{array}{l} Δ K E = W n e t \\ o r K_{1} - K_{1} = \int P d t \\ o r \frac{1}{2} m v^{2} = \int_{0}^{2} (\frac{3}{2} t^{2}) d t \\ o r v^{2} = {[\frac{t^{3}}{2}]}^{2}_{0} o r v = 2 m / s \end{array}$

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Power supplied to a particle of mass 2 kg varies with time as P=3t22 watt. Here t is in second. If velocity of particle at t =0 is v=0.The velocity of particle at time t = 2 s will be

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Power supplied to a particle of mass 2 kg varies with time as $P = (\frac{3 t^{2}}{2})$ watt. Here t is in second. If velocity of particle at t =0 is $v = 0$ .The velocity of particle at time t = 2 s will be