Power supplied to a particle of mass 2kg varies with times ‘t’ in seconds as P= 3 t 2 2 watt. If velocity of particle at t= 0 is v = 0. The velocity of particle at time t = 2s will be

From work energy theorem,ΔKE= W net or, K f − K i =∫Pdt or, 12mv2=∫02 32t2dtor, v 2 = t 3 2 0 2 or, v = 2 m/s

Power supplied to a particle of mass 2kg varies with times ‘t’ in seconds as P= 3 t 2 2 watt. If velocity of particle at t= 0 is v = 0. The velocity of particle at time t = 2s will be

From work energy theorem,ΔKE= W net or, K f − K i =∫Pdt or, 12mv2=∫02 32t2dtor, v 2 = t 3 2 0 2 or, v = 2 m/s

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Power supplied to a particle of mass 2kg varies with times ‘t’ in seconds as $P = (\frac{3 t^{2}}{2})$ watt. If velocity of particle at t= 0 is v = 0. The velocity of particle at time t = 2s will be

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1 m/s

2 m/s

4 m/s

2 \sqrt{2} m / s

answer is C.

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Detailed Solution

From work energy theorem,

$Δ K E = W_{n e t}$

or, $K_{f} - K_{i} = \int P d t$

or, $\frac{1}{2} m v^{2} = \int_{0}^{2} (\frac{3}{2} t^{2}) d t$

or, $v^{2} = {[\frac{t^{3}}{2}]}_{0}^{2}$

or, v = 2 m/s

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Power supplied to a particle of mass 2kg varies with times ‘t’ in seconds as P= 3 t 2 2 watt. If velocity of particle at t= 0 is v = 0. The velocity of particle at time t = 2s will be

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Power supplied to a particle of mass 2kg varies with times ‘t’ in seconds as $P = (\frac{3 t^{2}}{2})$ watt. If velocity of particle at t= 0 is v = 0. The velocity of particle at time t = 2s will be