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Q.

PQ  is a chord of length 16 cm  of a circle of radius 10 cm  . If the tangents at P  and Q  intersect at a point T  , then the length of TP  will be ____ cm.


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Detailed Solution

PQ  is a chord of length 16 cm  of a circle of radius 10 cm  . If the tangents at P  and Q  intersect at a point T  , then the length of TP  will be 10.67cm.
We must know the Perpendicular Bisector Pythagoras theorem where the hypotenuse is the longest side, as it is opposite to the angle of 90°.
Pythagoras Theorem formula can be written as,  Hypotenuse  2 =  Perpendicular  2 +  Base  2  
Given that PQ  is a chord which is 16 cm  and radius is 10 cm  .
Question ImageAssuming that,
  TR = y  
  TP = x  .
 The perpendicular drawn from the center to the chord bisects it,
PR =PQ PR+RQ =16 PR+PR =16 PR =8  
In ΔPOR  ,
PO 2 = OR 2 + PR 2 10 2 = OR 2 + 8 2 OR 2 =36 OR =6  
Using the Pythagoras Theorem in right angled ΔTPR  ,
T P 2 =T R 2 +P R 2 x 2 = y 2 + 8 2 x 2 = y 2 +64.....i)  
Using the Pythagoras Theorem in right angled ΔTPQ  ,
TO 2 = TP 2 + PO 2 (y+6) 2 = x 2 + 10 2 y 2 +12y+36 = x 2 +100 y 2 +12y = x 2 +64.....ii)  
Solving the equations (i) and (ii), we get,
  x=10.67 TP=10.67 cm  
Thus the length of TP  is 10.67 cm  .
 
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