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Q.

PQ  is a tangent touching a circle with centre O   and A   is the point of contact. If the measure of PAB=67°  , then the measure of AQB   will be


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a

73°  

b

64°  

c

53°  

d

44°   

answer is D.

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Detailed Solution

Given that PQ   is a tangent and PAB= 67 °   .
The chord is a diameter as it is passing through O which is the centre.
BAC= 90 °   (Angle in a semicircle is 90 °   )
By using the alternate segment theorem, we get,
PAB=ACB= 67 °  
In ΔABC  ,
ABC+ACB+BAC= 180 °   ABC+ 67 ° + 90 ° = 180 °    ABC= 23 °  
Calculating the value of BAQ  ,
Question Image In ΔABQ  ,
ABQ+AQB+BAQ= 180 °   23 ° +AQB+ 113 ° = 180 °    AQB= 44 °   Therefore, the measure of AQB = 44 °  .
Therefore the correct option will be 4.
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