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Q.

PQRS is a rectangle such that the perpendicular ST from S on PR divides S in the ratio 2:3. Determine TPQ in the ratio 2:3. Determine.


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a

36 °

b

40 °

c

56 °

d

64 °  

answer is A.

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Detailed Solution

Given, PQRS is a rectangle such that the perpendicular ST from S on PR divides S in the ratio 2:3.
Consider the rectangle PQRS as follows,
Question ImageWe have, to determine the angle measure TPQ .
So, using the given ratio, we will first find TSR .
Now, we know that every interior angle of a rectangle is a right angle.
Then, we can rewrite S as a sum of two angles as follows,
PST+TSR= 90
Now, as S is divided by ST in the ratio 2:3, so we have,
2x+3x= 90 5x= 90 x= 90 5 x= 18
So, we have, TSR=3x=3× 18 = 54
Now, the angle sum property of a triangle says that the sum of all the interior angles of a triangle is always
180 .
Applying this property on ΔSRT and substituting the known angle measures, we get,
TSR+STR+SRT= 180 54 + 90 +SRT= 180 144 +SRT= 180 SRT= 180 144 SRT= 36
Now, we know that opposite sides of a rectangle are always parallel to each other.
By this property, we can say that in the rectangle PQRS, PQ||RS and so, the diagonal PR acts as a transversal.
Then, by the property of alternate angles, we can say that,
TPQ=SRT TPQ= 36
Hence, the correct option is (1).
 
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