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Pressure over 1000 ml of a liquid is gradually increased from 1 bar to 1001 bar under adiabatic conditions. If the final volume of the liquid is 990 ml and there is linear variation of volume with pressure, the value of $ΔU$ of the process is (abc) joule where a, b and c are integer then represent your answer as (a+b+c).

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answer is 6.

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Detailed Solution

$A (l, 1000 m l, 1 bar) \to_{}^{} A (l, 990 m l, 1001 bar)$

$W = \frac{1}{2} (P_{1} + P_{2}) (V_{1} - V_{2})$

W = 5.01 L-bar = 5.01 x 100 = 501

$a + b + c = 5 + 0 + 1 = 6$

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