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Q.

Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is $ρ_{0}$ . Density at B will be

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a

$\frac{3}{2} ρ_{0}$

b

$\frac{4}{3} ρ_{0}$

c

$\frac{3}{4} ρ_{0}$

d

$2 ρ_{0}$

answer is B.

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Detailed Solution

$\begin{array}{l} PV = nRT \\ \frac{p}{ρ} \propto T \end{array}$

$\frac{P_{0} ρ}{ρ_{0} 3 P_{0}} = \frac{T_{0}}{2 T_{0}} ρ = \frac{3}{2} ρ_{0}$

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