Production of iron in blast furnace follows the following equation ${\mathrm{Fe}}_3{\mathrm{O}}_4\left(\mathrm{s}\right)+4\mathrm{CO}\left(\mathrm{g}\right)\to 3\mathrm{Fe}\left(\mathrm{l}\right)+4{\mathrm{CO}}_2\left(\mathrm{g}\right)$ when 4.640 kg of ${\mathrm{Fe}}_3{\mathrm{O}}_4$ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is :

[Given: Molar Atomic mass $\left(g{\mathrm{mol}}^{-1}\right):\mathrm{Fe}=56$

            Molar Atomic mass $\left(g{\mathrm{mol}}^{-1}\right):\mathrm{O}=16$

            Molar Atomic mass $\left.\left(g{\mathrm{mol}}^{-1}\right):\mathrm{C}=12\right]$