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Q.

Propane reacts with chlorine in sunlight to give two products. $1 -$ chloropropane is obtained in $44 %$ yield and $2 -$ chloropropane is obtained in $56 %$ yield of the total product. What will be the percent yield of the major product obtained when butane is treated with ${CI}_{2}$ in similar conditions. (Round answer as nearest integer)

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answer is 72.

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Detailed Solution

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Reactivity of $2^{°} & 1^{°} H = 3.8 : 1$

Reactive of $1^{°} H = 6 \times 1 = 6$

Reactive of $2^{°} H = 3.8 \times 4 = 15.2$

$Total = 21.2$

Amount of primary product $= \frac{6}{21.2} \times 100 = 28.30$

Amount of secondary product $= \frac{15.2}{21.2} \times 100 = 71.7 \approx 72$

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Propane reacts with chlorine in sunlight to give two products. 1-chloropropane is obtained in 44% yield and 2-chloropropane is obtained in 56% yield of the total product. What will be the percent yield of the major product obtained when butane is treated with CI2 in similar conditions. (Round answer as nearest integer)